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31 May 2024
N 05:59 | Logarithmic Integral and Eulerian Logarithmic Integral Differ by Constant diffhist +2,080 Prime.mover talk contribs (Created page with "== Theorem == <onlyinclude> Let $x \in \R$ be a real number such that $x > 2$. Let $\map \li x$ denote the logarithmic integral of $x$. Let $\map \Li x$ denote the Eulerian logarithmic integral of $x$. Then $\map \li x - \map \Li x$ is a constant. </onlyinclude> == Proof == {{begin-eqn}} {{eqn | l = \map \li x - \map \Li x | r = \...") |