Cantor Space is Complete Metric Space

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $T = \struct {\CC, \tau_d}$ be the Cantor space.


Then $T$ is a complete metric space.


Proof

We have that the Cantor space is a metric subspace of the real number space $\R$, and hence a metric space.

We also have Cantor Space is Compact.

The result follows from Compact Metric Space is Complete.

$\blacksquare$


Sources