Cartesian Product Null
From ProofWiki
Theorem
- $S \times T = \varnothing \iff S = \varnothing \lor T = \varnothing$
Thus:
- $S \times \varnothing = \varnothing = \varnothing \times T$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle S \times T\) | \(\ne\) | \(\displaystyle \varnothing\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle \exists \left({s, t}\right)\) | \(\in\) | \(\displaystyle S \times T\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of Empty Set | ||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle \exists s \in S\) | \(\land\) | \(\displaystyle \exists t \in T\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of Cartesian Product | ||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle S \ne \varnothing\) | \(\land\) | \(\displaystyle T \ne \varnothing\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of Empty Set | ||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle \neg (S = \varnothing\) | \(\lor\) | \(\displaystyle T = \varnothing)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | De Morgan's Laws |
So by the Rule of Transposition:
- $S = \varnothing \lor T = \varnothing \iff S \times T = \varnothing$
$\blacksquare$
Sources
- Paul R. Halmos: Naive Set Theory (1960)... (previous)... (next): $\S 6$: Ordered Pairs
- Seth Warner: Modern Algebra (1965)... (previous)... (next): Exercise $1.2$
- T.S. Blyth: Set Theory and Abstract Algebra (1975): $\S 3$
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 8$