Combination Theorem for Limits of Functions/Combined Sum Rule
From ProofWiki
Theorem
Let $X$ be one of the standard number fields $\Q, \R, \C$.
Let $f$ and $g$ be functions defined on an open subset $S \subseteq X$, except possibly at the point $c \in S$.
Let $f$ and $g$ tend to the following limits:
- $\displaystyle \lim_{x \to c} \ f \left({x}\right) = l$
- $\displaystyle \lim_{x \to c} \ g \left({x}\right) = m$
Let $\lambda, \mu \in X$ be arbitrary numbers in $X$.
Then:
- $\displaystyle \lim_{x \to c} \left({\lambda f \left({x}\right) + \mu g \left({x}\right)}\right) = \lambda l + \mu m$
Proof
Let $\left \langle {x_n} \right \rangle$ be any sequence of points of $S$ such that:
- $\forall n \in \N^*: x_n \ne c$
- $\displaystyle \lim_{n \to \infty} x_n = c$
By Limit of Function by Convergent Sequences:
- $\displaystyle \lim_{n \to \infty} f \left({x_n}\right) = l$
- $\displaystyle \lim_{n \to \infty} g \left({x_n}\right) = m$
By the Combined Sum Rule for Sequences:
- $\displaystyle \lim_{n \to \infty} \left({\lambda f \left({x_n}\right) + \mu g \left({x_n}\right)}\right) = \lambda l + \mu m$
Applying Limit of Function by Convergent Sequences again, we get:
- $\displaystyle \lim_{x \to c} \left({\lambda f \left({x}\right) + \mu g \left({x}\right)}\right) = \lambda l + \mu m$
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 8.12 \ \text{(i)}$