Combination Theorem for Sequences/Quotient Rule
Theorem
Let $X$ be one of the standard number fields $\Q, \R, \C$.
Let $\left \langle {x_n} \right \rangle$ and $\left \langle {y_n} \right \rangle$ be sequences in $X$.
Let $\left \langle {x_n} \right \rangle$ and $\left \langle {y_n} \right \rangle$ be convergent to the following limits:
- $\displaystyle\lim_{n \to \infty} x_n = l, \lim_{n \to \infty} y_n = m$
Then:
- $\displaystyle\lim_{n \to \infty} \frac {x_n} {y_n} = \frac l m$
provided that $m \ne 0$.
Proof
As $y_n \to m$ as $n \to \infty$, it follows from Modulus of Limit that $\left\vert{y_n}\right\vert \to \left\vert{m}\right\vert$ as $n \to \infty$.
As $m \ne 0$, it follows from the definition of the modulus of $m$ that $\left\vert{m}\right\vert > 0$.
From Sequence Converges to Within Half Limit, we have $\exists N: \forall n > N: \left\vert{y_n}\right\vert > \frac {\left\vert{m}\right\vert} 2$.
Now, for $n > N$, consider:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \left\vert \frac {x_n} {y_n} - \frac {l} {m} \right\vert\) | \(=\) | \(\displaystyle \left\vert \frac {m x_n - y_n l} {m y_n} \right\vert\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(<\) | \(\displaystyle \frac 2 {\left\vert{m}\right\vert^2} \left\vert{m x_n - y_n l}\right\vert\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
By the above, $m x_n - y_n l \to ml - ml = 0$ as $n \to \infty$.
The result follows by the Squeeze Theorem for Sequences of Complex Numbers (which applies as well to real as to complex sequences).
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 4.8 \ \text{(iii)}$