Complements Invert Subsets

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Theorem

$S \subseteq T \iff \complement \left({T}\right) \subseteq \complement \left({S}\right)$

where:


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle S\) \(\subseteq\) \(\displaystyle T\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle S \cap T\) \(=\) \(\displaystyle S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Intersection with Subset is Subset‎          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \complement \left({S \cap T}\right)\) \(=\) \(\displaystyle \complement \left({S}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Relative Complement of Relative Complement          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \complement \left({S}\right) \cup \complement \left({T}\right)\) \(=\) \(\displaystyle \complement \left({S}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          De Morgan's Laws          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \complement \left({T}\right)\) \(\subseteq\) \(\displaystyle \complement \left({S}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Union with Superset is Superset          

$\blacksquare$


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