Congruence to an Integer less than Modulus
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Theorem
Let $m \in \Z$.
Then each integer is congruent (modulo $m$) to precisely one of the integers $0, 1, \ldots, m - 1$.
Proof
Proof of Existence
Let $a \in \Z$.
Then from the Division Theorem: $\exists r \in \left\{{0, 1, \ldots, m-1}\right\}: a \equiv r \pmod m$.
Proof of Uniqueness
Suppose that:
- $\exists r_1, r_2 \in \left\{{0, 1, \ldots, m-1}\right\}: a \equiv r_1 \pmod m \land a \equiv r_2 \pmod m$
Then:
- $\exists r_1, r_2 \in \Z: a = q_1 m + r_1 = q_2 m + r_2$
This contradicts the uniqueness clause in the Division Theorem.
$\blacksquare$
Sources
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 14.2 \ \text{(ii)}$