Conjugacy Classes of Center Elements are Singletons

From ProofWiki
Jump to: navigation, search

Contents

Theorem

Let $G$ be a group.

Let $Z \left({G}\right)$ be the center of $G$.


The elements of $Z \left({G}\right)$ form singleton conjugacy classes, and the elements of $G \setminus Z \left({G}\right)$ belong to multi-element conjugacy classes.


Corollary

The number of single-element conjugacy classes of $G$ is the order of $Z \left({G}\right)$ and divides $G$.


Proof

Let $\mathrm C_a$ be the conjugacy class of $a$ in $G$.


\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle a\) \(\in\) \(\displaystyle Z \left({G}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \forall x \in G: x a\) \(=\) \(\displaystyle a x\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \forall x \in G: x a x^{-1}\) \(=\) \(\displaystyle a\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \mathrm C_a\) \(=\) \(\displaystyle \left\{ {a}\right\}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    

$\blacksquare$


Sources

Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense