Conjugate of a Set by Identity

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Theorem

Let $\left({G, \circ}\right)$ be a group whose identity is $e$.

Let $S \subseteq G$.


Then the conjugate of $S$ by $e$ is $S$:

$S^e = S$


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle S^e\) \(=\) \(\displaystyle \left\{ {y \in G: \exists x \in S: y = e \circ x \circ e^{-1} }\right\}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Conjugate of a Set          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle \left\{ {y \in G: \exists x \in S: y = x}\right\}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Identity          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    

$\blacksquare$


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