Definition:Image

From ProofWiki
Jump to: navigation, search

Contents

Definition

The definition of a relation given here as a subset of the Cartesian product of two sets gives a "static" sort of feel to the concept.

However, we can also consider a relation as being an operator, where you feed an element $s \in S$ (or a subset $S_1 \subseteq S$) in at one end, and you get a set of elements $T_s \subseteq T$ out of the other.

Thus we arrive at the following definition.


Image of a Relation

Let $\mathcal R \subseteq S \times T$ be a relation.

The image (or image set) of $\mathcal R$ is the set:

$\operatorname{Im} \left ({\mathcal R}\right) = \mathcal R \left ({S}\right) = \left\{ {t \in T: \exists s \in S: \left({s, t}\right) \in \mathcal R}\right\}$


Image of an Element

Let $\mathcal R \subseteq S \times T$ be a relation.

Let $s \in S$.

The image of $s$ by $\mathcal R$ is defined as:

$\operatorname{Im} \left ({s}\right) = \mathcal R \left ({s}\right) = \left\{ {t \in T: \left({s, t}\right) \in \mathcal R}\right\}$

That is, $\mathcal R \left ({s}\right)$ is the set of all elements of the codomain of $\mathcal R$ related to $s$ by $\mathcal R$.


Image of a Subset

Let $A \subseteq S$ be a subset of $S$.

Then the image set (of $A$ by $\mathcal R$) is:

$\operatorname{Im} \left ({A}\right) = \mathcal R \left ({A}\right) = \left\{ {t \in T: \exists s \in A: \left({s, t}\right) \in \mathcal R}\right\}$

If $A = \operatorname{Dom} \left({\mathcal R}\right)$, we have:

$\operatorname{Im} \left ({\operatorname{Dom} \left({\mathcal R}\right)}\right) = \mathcal R \left ({\operatorname{Dom} \left({\mathcal R}\right)}\right) = \operatorname{Im} \left ({\mathcal R}\right)$


It is also clear that $\forall s \in S: \mathcal R \left ({s}\right) = \mathcal R \left ({\left\{{s}\right\}}\right)$.


While the use of $\operatorname{Im} \left ({A}\right)$ etc. can be useful, it is arguably preferable in some situations to use $\mathcal R \left ({A}\right)$, as this makes it more apparent to exactly what relation the image refers.


Some authors use $\mathcal R^\to \left ({A}\right)$ for what we have here as $\mathcal R \left ({A}\right)$.


Image of a Mapping

The image (or image set) of a mapping $f: S \to T$ is the set:

$\operatorname{Im} \left ({f}\right) = f \left ({S}\right) = \left\{ {t \in T: \exists s \in S: f \left({s}\right) = t}\right\}$


Notes

Some sources refer to this as the direct image of a (usually) mapping, in order to differentiate it from an inverse image.

Rather than apply a relation $\mathcal R$ (or mapping $f$) directly to a subset $A$, those sources prefer to define the mapping induced by $\mathcal R$ or $f$ as a separate concept in its own right.


Also see

  • Mapping, in which the context of an image is usually encountered.
Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense