Ring of Polynomial Forms
Contents |
Theorem
Let $\left({R, +, \circ}\right)$ be a commutative ring with unity.
Let $A=R \left[\{{X_j:j\in J}\}\right]$ be the set of all polynomial forms over $R$ in the indeterminates $\{{X_j:j\in J}\}$.
Let $Z$ be the set of all multiindices indexed by $J$.
Let $+$ and $\circ$ denote the standard addition and multiplication of polynomial forms.
Then $\left({A, +, \circ}\right)$ is a commutative ring with unity.
Proof
We must show that the following axioms are satisfied:
Additive axioms
| A1: | $A$ is closed under addition; |
| A2: | Addition in $A$ is associative; |
| A3: | $A$ contains an additive identity; |
| A4: | Each $f \in A$ has an additive inverse; |
| A5: | Addition in $A$ is commutative; |
Multiplicative axioms
| M1: | $A$ is closed under multiplication; |
| M2: | Multiplication in $A$ is associative; |
| M3: | $A$ contains a multiplicative identity; |
| M4: | Multiplication in $A$ is commutative; |
| D: | Multiplication distributes over addition in $A$. |
Proof of the additive axioms
A1:
This is shown by Polynomials Closed under Addition.
A2-A5:
According to the formal definition, a polynomial is a map from the free commutative monoid to $R$.
Now observe that addition of polynomial forms is induced by addition in $R$.
Therefore:
- A2 is shown by Induced Structure Associative
- A3 is shown by Induced Structure Identity
- A4 is shown by Induced Structure Inverse
- A5 is shown by Induced Structure Commutative
Proof of the multiplicative axioms
M1:
This is shown by Polynomials Closed under Ring Product.
Multiplication of polynomial forms is not induced by multiplication in $R$, so we must show the multiplicative axioms by hand.
M2:
This is shown by Multiplication of Polynomials is Associative.
M3:
This is shown by Polynomials Contain Multiplicative Identity.
M4:
This is shown by Multiplication of Polynomials is Commutative.
D:
This is shown by Multiplication of Polynomials Distributes over Addition.
Therefore, all of the axioms of a commutative ring with unity are satisfied.
$\blacksquare$