Derivative of Powers of Functions
From ProofWiki
Contents |
Theorem
Let $u \left({x}\right), v \left({x}\right)$ be real functions which are differentiable on $\R$.
Then:
- $D_x \left({u^v}\right) = v u^{v-1} D_x \left({u}\right) + u^v \ln u D_x \left({v}\right)$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle D_x \left({u^v}\right)\) | \(=\) | \(\displaystyle D_x \left({e^{v \ln u} }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Powers of Real Numbers | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle e^{v \ln u} D_x \left({v \ln u}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Chain Rule and Derivative of Exponential Function | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle e^{v \ln u} \left({\ln u D_x \left({v}\right) + v D_x \left({\ln u}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Product Rule | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle u^v \left({\ln u D_x \left({v}\right) + \frac v u D_x \left({u}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Chain Rule | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle v u^{v-1} D_x \left({u}\right) + u^v \ln u D_x \left({v}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | gathering terms |
$\blacksquare$
Note
When $u = x$ and $v = n$ where $n$ is constant, we get the Power Rule for Derivatives:
- $D_x \left({x^n}\right) = n x^{n-1}$
When $v = x$ and $u = a$ where $a$ is constant, we get the Derivative of Exponential Function:
- $D_x \left({a^x}\right) = a^x \ln a$