Diagonal Relation Equivalence

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Theorem

The diagonal relation $\Delta_S$ on $S$ is always an equivalence in $S$.


Proof

Checking in turn each of the criteria for equivalence:


Reflexive

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\) \(\displaystyle \forall x \in S: \left({x, x}\right) \in \Delta_S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Diagonal Relation          

So $\Delta_S$ is reflexive.

$\Box$


Symmetric

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\) \(\displaystyle \forall x, y \in S: \left({x, y}\right) \in \Delta_S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle x = y\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Diagonal Relation          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle y = x\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Equality is Symmetric          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left({y, x}\right) \in \Delta_S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Diagonal Relation          

So $\Delta_S$ is symmetric.

$\Box$


Transitive

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\) \(\displaystyle \forall x, y, z \in S: \left({x, y}\right) \in \Delta_S \land \left({y, z}\right) \in \Delta_S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle x = y \land y = z\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Diagonal Relation          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle x = z\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Equality is Transitive          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left({x, z}\right) \in \Delta_S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Diagonal Relation          

So $\Delta_S$ is transitive.

$\blacksquare$


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