Equality is Symmetric

From ProofWiki
Jump to navigation Jump to search

Theorem

Equality is symmetric.


That is:

$\forall a, b: a = b \implies b = a$


Proof

\(\ds a\) \(=\) \(\ds b\)
\(\ds \vdash \ \ \) \(\ds \map P a\) \(\iff\) \(\ds \map P b\) Leibniz's Law
\(\ds \vdash \ \ \) \(\ds \map P b\) \(\iff\) \(\ds \map P a\) Biconditional is Commutative
\(\ds \vdash \ \ \) \(\ds b\) \(=\) \(\ds a\) Leibniz's Law

$\blacksquare$


Also see


Sources