Integral of Function plus Constant
From ProofWiki
Theorem
Let $f$ be a real function which is continuous on the closed interval $\left[{a .. b}\right]$.
Let $c$ be a constant.
Then:
- $\displaystyle \int_a^b \left({f \left({t}\right) + c}\right) \ \mathrm dt = \int_a^b f \left({t}\right)\ \mathrm dt + c \left({b - a}\right)$
Proof
Let $P = \left\{{x_0, x_1, x_2, \ldots, x_n}\right\}$ be a subdivision of $\left[{a .. b}\right]$.
Let $L^{\left({f+c}\right)} \left({P}\right)$ be the lower sum of $f \left({x}\right) + c$ on $\left[{a .. b}\right]$ belonging to $P$.
Let:
- $\displaystyle m_k^{\left({f+c}\right)} = \inf_{x \in \left[{x_{k - 1} .. x_k}\right]} \left({f \left({x}\right) + c}\right)$
where $k \in \left\{{0, 1, \ldots, n}\right\}$.
So:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle m_k^{\left({f+c}\right)}\) | \(=\) | \(\displaystyle \inf_{x \in \left[{x_{k - 1} .. x_k}\right]} \left({f \left({x}\right) + c}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle c + \inf_{x \in \left[{x_{k - 1} .. x_k}\right]} \left({f \left({x}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle c + m_k^{\left({f}\right)}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
It follows that:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle L^{\left({f+c}\right)} \left({P}\right)\) | \(=\) | \(\displaystyle \sum_{k=1}^n m_k^{\left({f+c}\right)} \left({x_k - x_{k - 1} }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sum_{k=1}^n m_k^{\left({f}\right)} \left({x_k - x_{k - 1} }\right) + c \sum_{k=1}^n \left({x_k - x_{k - 1} }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle L^{\left({f}\right)} \left({P}\right) + c \left({b - a}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | as $\displaystyle \sum_{k=1}^n \left({x_k - x_{k - 1} }\right)$ telescopes |
So from the definition of definite integral, it follows that:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \int_a^b \left({f \left({t}\right) + c}\right)\ \mathrm dt\) | \(=\) | \(\displaystyle \sup_P \left({L^{\left({f+c}\right)} \left({P}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sup_P \left({L^{\left({f}\right)} \left({P}\right) + c \left({b - a}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sup_P \left({L^{\left({f}\right)} \left({P}\right)}\right) + c \left({b - a}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \int_a^b f \left({t}\right) \ \mathrm dt + c \left({b - a}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 13.7$