Intersection is Associative

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Theorem

Set intersection is associative:

$A \cap \left({B \cap C}\right) = \left({A \cap B}\right) \cap C$


Proof

\(\displaystyle \) \(\displaystyle x \in A \cap \left({B \cap C}\right)\) \(\iff\) \(\displaystyle x \in A \land \left({x \in B \land x \in C}\right)\) \(\displaystyle \)          Definition of intersection          
\(\displaystyle \) \(\displaystyle \) \(\iff\) \(\displaystyle \left({x \in A \land x \in B}\right) \land x \in C\) \(\displaystyle \)          Rule of Association          
\(\displaystyle \) \(\displaystyle \) \(\iff\) \(\displaystyle x \in \left({A \cap B}\right) \cap C\) \(\displaystyle \)          Definition of intersection          


Therefore, $x \in A \cap \left({B \cap C}\right)$ iff $x \in \left({A \cap B}\right) \cap C$.

Thus it has been shown that $A \cap \left({B \cap C}\right) = \left({A \cap B}\right) \cap C$.

$\blacksquare$


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