Intersection is Commutative

From ProofWiki
Jump to: navigation, search

Contents

Theorem

Set intersection is commutative:

$S \cap T = T \cap S$


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle x\) \(\in\) \(\displaystyle \left({S \cap T}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle x \in S\) \(\land\) \(\displaystyle x \in T\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Set Intersection          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle x \in T\) \(\land\) \(\displaystyle x \in S\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Rule of Commutation          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle x\) \(\in\) \(\displaystyle \left({T \cap S}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Set Intersection          

$\blacksquare$


Also see


Sources

Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense