Intersection with Empty Set

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Theorem

The intersection of any set with the empty set is itself the empty set:

$S \cap \varnothing = \varnothing$


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle S \cap \varnothing\) \(\subseteq\) \(\displaystyle \varnothing\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Intersection Subset          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \varnothing\) \(\subseteq\) \(\displaystyle S \cap \varnothing\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Empty Set Subset of All          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle S \cap \varnothing\) \(=\) \(\displaystyle \varnothing\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of Set Equality          

$\blacksquare$


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