Intersection with Relative Complement
From ProofWiki
Theorem
The intersection of a set and its relative complement is the empty set:
- $T \cap \complement_S \left({T}\right) = \varnothing$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle T \cap \complement_S \left({T}\right)\) | \(=\) | \(\displaystyle \left({S \setminus T}\right) \cap T\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of relative complement | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \varnothing\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Set Difference Intersection Second Set is Empty Set |
$\blacksquare$
Sources
- Paul R. Halmos: Naive Set Theory (1960)... (previous)... (next): $\S 5$: Complements and Powers
- Seth Warner: Modern Algebra (1965)... (previous)... (next): $\S 3$: Theorem $3.2$
- T.S. Blyth: Set Theory and Abstract Algebra (1975): $\S 1$