Irrationals are Everywhere Dense in Reals
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Theorem
Topology
Let $T = \struct {\R, \tau}$ denote the real number line with the usual (Euclidean) topology.
Let $\R \setminus \Q$ be the set of irrational numbers.
Then $\R \setminus \Q$ is everywhere dense in $T$.
Normed Vector Space
Let $\struct {\R, \size {\, \cdot \,} }$ be the normed vector space of real numbers.
Let $\R \setminus \Q$ be the set of irrational numbers.
Then $\R \setminus \Q$ is everywhere dense in $\struct {\R, \size {\, \cdot \,} }$