Monomorphism Image Isomorphic to Domain
Theorem
The image of a monomorphism is isomorphic to its domain.
That is, if $\phi \left({S_1}\right) \to S_2$ is a monomorphism, then:
- $\phi \left({S_1}\right) \to \operatorname{Im} \left({\phi}\right)$
is an isomorphism.
Proof
Let $\left({S_1, \circ_1}\right)$ and $\left({S_2, \circ_2}\right)$ be closed algebraic structures.
Let $\phi$ be a monomorphism from $\left({S_1, \circ_1}\right)$ to $\left({S_2, \circ_2}\right)$.
Let $T = \operatorname{Im} \left({\phi}\right)$ be the image of $\phi$.
By Morphism Property Preserves Closure, $\left({T, \circ_2}\right)$ is closed.
As $\phi$ is a monomorphism, it is an injection.
As $\phi \to \operatorname{Im} \left({\phi}\right)$ is a surjection from Surjection iff Image equals Codomain, we see that $\phi \to \operatorname{Im} \left({\phi}\right)$ is a bijection.
Thus $\phi \to \operatorname{Im} \left({\phi}\right)$ is a bijective homomorphism and hence from the definition, an isomorphism.
$\blacksquare$
Sources
- Seth Warner: Modern Algebra (1965)... (previous)... (next): $\S 12$
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 47.6$