NOR With Equal Arguments
From ProofWiki
Theorem
Let $\downarrow$ signify the NOR operation.
Then for any proposition $p$:
- $p \downarrow p \dashv \vdash \neg p$
That is, the NOR of a proposition with itself corresponds to the negation operator.
Proof by Tableau
Proceed by the tableau method:
| Line | Pool | Formula | Rule | Depends upon | |
|---|---|---|---|---|---|
| 1 | 1 | $p \downarrow p$ | $\mathrm P$ | (None) | |
| 2 | 1 | $\neg \left({p \lor p}\right)$ | By definition | 1 | |
| 3 | 1 | $\neg p$ | $\mathrm {Idemp}$ | 2 |
| Line | Pool | Formula | Rule | Depends upon | |
|---|---|---|---|---|---|
| 1 | 1 | $\neg p$ | $\mathrm P$ | (None) | |
| 2 | 1 | $\neg \left({p \lor p}\right)$ | $\mathrm {Idemp}$ | 1 | |
| 3 | 1 | $p \downarrow p$ | By definition | 2 |
$\blacksquare$
Proof by Truth Table
Apply the Method of Truth Tables:
- $\begin{array}{|ccc||cc|} \hline p & \downarrow & p & \neg & p \\ \hline F & T & F & T & F \\ T & F & T & F & T \\ \hline \end{array}$
As can be seen by inspection, the truth values under the main connectives match for all models.
$\blacksquare$