Polynomials Addition is Associative
From ProofWiki
Theorem
Addition of polynomials is an associative operation.
Proof
Let $(R, +, \circ)$ be a commutative ring with unity.
Let $\left\{{X_j: j \in J}\right\}$ be a set of indeterminates.
Let $Z$ be the set of all multiindices indexed by $\left\{{X_j: j \in J}\right\}$.
Let
- $\displaystyle f = \sum_{k\in Z} a_k \mathbf X^k$
- $\displaystyle g = \sum_{k\in Z} b_k \mathbf X^k$
- $\displaystyle h = \sum_{k\in Z} c_k \mathbf X^k$
be arbitrary polynomials in the indeterminates $\left\{{X_j: j \in J}\right\}$ over $R$.
Then
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \left({ f + g }\right) + h\) | \(=\) | \(\displaystyle \sum_{k\in Z} \left({ \left({ a_k + b_k }\right) + c_k }\right) \mathbf X^k\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | applying the definition of polynomial addition twice | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \sum_{k\in Z} \left({ a_k + \left({ b_k + c_k }\right) }\right) \mathbf X^k\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | because addition in $R$ is associative | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle f + \left({ g + h }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | applying the definition of polynomial addition twice |
$\blacksquare$