Power Reduction Formulas

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Theorem

$\sin^2x = \dfrac {1 - \cos2x} 2$
$\cos^2x = \dfrac {1 + \cos2x} 2$
$\tan^2x = \dfrac {1 - \cos2x} {1 + \cos2x}$

where $\sin, \cos, \tan$ are sine, cosine and tangent.


Proof

Proof for Sine Squared

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle 1 - 2 \sin^2x\) \(=\) \(\displaystyle \cos2x\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Corollary to Double Angle Formulas          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \sin^2x\) \(=\) \(\displaystyle \frac {\cos2x - 1} {-2}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          solving for $\sin^2x$          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle \frac {1 - \cos2x} 2\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          multiplying by $1 = \frac {-1}{-1}$ and rearranging terms          

$\blacksquare$


Proof for Cosine Squared

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle 2 \cos^2x - 1\) \(=\) \(\displaystyle \cos2x\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Corollary to Double Angle Formulas          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \cos^2x\) \(=\) \(\displaystyle \frac {1 + \cos2x} 2\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          solving for $\cos^2x$          

$\blacksquare$


Proof for Tangent Squared

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \tan^2x\) \(=\) \(\displaystyle \frac {\sin^2x} {\cos^2x}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          definition of tangent          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle \frac {\frac {1 - \cos2x} 2} {\frac {\cos2x + 1} 2}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          from above          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle \frac {1 - \cos2x} {1 + \cos2x}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          multiplying by $1 = \frac 2 2$          

$\blacksquare$


Comment

The identities for $\sin^2x$ and $\cos^2x$ can be useful for integrating expressions of the form:

$\displaystyle \int \sin^mx \ \cos^nx \ \mathrm dx$

where $m$ and $n$ are both even.

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