Precedes Next
From ProofWiki
Theorem
Let $\left({S, \circ, \preceq}\right)$ be a naturally ordered semigroup.
Then:
- $\forall n \in S: n \prec n \circ 1$
Consequently:
- $\forall n, p \in S: n \prec p \iff n \circ 1 \preceq p$
Proof
From Zero Precedes One, we have that $0 \prec 1$.
So:
- $n = n \circ 0 \prec n \circ 1$
by Cancellability in Naturally Ordered Semigroup.
To show that $n \prec p \implies n \circ 1 \preceq p$:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle n\) | \(\prec\) | \(\displaystyle p\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle n \circ 0\) | \(\ne\) | \(\displaystyle p\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of zero | ||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle p \ominus n\) | \(\ne\) | \(\displaystyle 0\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of minus | ||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle p \ominus n\) | \(\notin\) | \(\displaystyle S^*\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Zero Complement | ||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle 1\) | \(\preceq\) | \(\displaystyle p \ominus n\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Smallest Element of Zero Complement of Naturally Ordered Semigroup | ||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle n \circ 1\) | \(\preceq\) | \(\displaystyle p\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of minus |
To show that $n \circ 1 \preceq p \implies n \prec p$:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle n\) | \(\prec\) | \(\displaystyle n \circ 1\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | from above | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle n \circ 1\) | \(\preceq\) | \(\displaystyle p\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | By hypothesis | ||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle n\) | \(\prec\) | \(\displaystyle p\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Transitivity of $\preceq$ |
$\blacksquare$
Sources
- Seth Warner: Modern Algebra (1965)... (previous)... (next): $\S 16$: Theorem $16.4$