Precedes Next

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Theorem

Let $\left({S, \circ, \preceq}\right)$ be a naturally ordered semigroup.


Then:

$\forall n \in S: n \prec n \circ 1$


Consequently:

$\forall n, p \in S: n \prec p \iff n \circ 1 \preceq p$


Proof

From Zero Precedes One, we have that $0 \prec 1$.

So:

$n = n \circ 0 \prec n \circ 1$

by Cancellability in Naturally Ordered Semigroup.


To show that $n \prec p \implies n \circ 1 \preceq p$:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle n\) \(\prec\) \(\displaystyle p\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle n \circ 0\) \(\ne\) \(\displaystyle p\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of zero          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle p \ominus n\) \(\ne\) \(\displaystyle 0\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of minus          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle p \ominus n\) \(\notin\) \(\displaystyle S^*\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Zero Complement          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle 1\) \(\preceq\) \(\displaystyle p \ominus n\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Smallest Element of Zero Complement of Naturally Ordered Semigroup          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle n \circ 1\) \(\preceq\) \(\displaystyle p\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of minus          


To show that $n \circ 1 \preceq p \implies n \prec p$:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle n\) \(\prec\) \(\displaystyle n \circ 1\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          from above          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle n \circ 1\) \(\preceq\) \(\displaystyle p\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          By hypothesis          
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle n\) \(\prec\) \(\displaystyle p\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Transitivity of $\preceq$          

$\blacksquare$


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