Product of Absolute Values

From ProofWiki
Jump to: navigation, search

Contents

Theorem

Let $\left({D, +, \times}\right)$ be an ordered integral domain.

For all $a \in D$, let $\left \vert{a}\right \vert$ denote the absolute value of $a$.


Then:

$\left \vert{a}\right \vert \times \left \vert{b}\right \vert = \left \vert{a \times b}\right \vert$


Corollary

For the number systems $\Z, \Q, \R$:

$\left \vert{a}\right \vert \cdot \left \vert{b}\right \vert = \left \vert{a b}\right \vert$


Proof

Let $P$ be the positivity property on $D$, let $<$ be the ordering induced by it, and let $N$ be the negativity property on $D$.


We consider all possibilities in turn.


$(1): \quad a = 0$ or $b = 0$

In this case, both the LHS $\left \vert{a}\right \vert \times \left \vert{b}\right \vert$ and the RHS are equal to zero.

So:

$\left \vert{a}\right \vert \times \left \vert{b}\right \vert = \left \vert{a \times b}\right \vert$


$(2): \quad P \left({a}\right), P \left({b}\right)$

First:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle P \left({a}\right), P \left({b}\right)\) \(\implies\) \(\displaystyle \left \vert{a}\right \vert = a, \left \vert{b}\right \vert = b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a}\right \vert \times \left \vert{b}\right \vert = a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    

Then:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \quad P \left({a}\right), P \left({b}\right)\) \(\implies\) \(\displaystyle P \left({a \times b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Positivity property: $(2)$          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a \times b}\right \vert = a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          

So:

$\left \vert{a}\right \vert \times \left \vert{b}\right \vert = \left \vert{a \times b}\right \vert$


$(3): \quad P \left({a}\right), N \left({b}\right)$

First:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle P \left({a}\right), N \left({b}\right)\) \(\implies\) \(\displaystyle \left \vert{a}\right \vert = a, \left \vert{b}\right \vert = -b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a}\right \vert \times \left \vert{b}\right \vert = - a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Negative Product          

Then:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \quad P \left({a}\right), N \left({b}\right)\) \(\implies\) \(\displaystyle N \left({a \times b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Properties of Negativity: $(5)$          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle P \left({- a \times b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of negativity property          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a \times b}\right \vert = -a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          

So:

$\left \vert{a}\right \vert \times \left \vert{b}\right \vert = \left \vert{a \times b}\right \vert$

Similarly $N \left({a}\right), P \left({b}\right)$.


$(4): \quad N \left({a}\right), N \left({b}\right)$

First:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle N \left({a}\right), N \left({b}\right)\) \(\implies\) \(\displaystyle \left \vert{a}\right \vert = -a, \left \vert{b}\right \vert = -b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a}\right \vert \times \left \vert{b}\right \vert = a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Negative Product          

Then:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \quad N \left({a}\right), N \left({b}\right)\) \(\implies\) \(\displaystyle P \left({a \times b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Properties of Negativity: $(4)$          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle P \left({a \times b}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of negativity property          
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\implies\) \(\displaystyle \left \vert{a \times b}\right \vert = a \times b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Definition of absolute value          

So:

$\left \vert{a}\right \vert \times \left \vert{b}\right \vert = \left \vert{a \times b}\right \vert$


In all cases the result holds.

$\blacksquare$


Proof of Corollary

Follows directly from:

$\blacksquare$


Sources

Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense