Quotient Group of Direct Products
Theorem
Let $G$ and $G'$ be groups.
Let:
- $H \triangleleft G$
- $H' \triangleleft G'$
where $\triangleleft$ denotes the relation of being a normal subgroup.
Then:
- $(1): \quad \left({H \times H'}\right) \triangleleft \left({G \times G'}\right)$
- $(2): \quad \left({G \times G'}\right) / \left({H \times H'}\right)$ is isomorphic to $\left({G / H}\right) \times \left({G' / H'}\right)$
where:
- $H \times H'$ denotes the group direct product of $H$ and $H'$
- $G / H$ denotes the quotient group of $G$ by $H$.
Proof
$(1): \quad \left({H \times H'}\right) \triangleleft \left({G \times G'}\right)$:
Let $\left({x, x'}\right) \in G \times G'$ and $\left({y, y'}\right) \in H \times H'$.
Then:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \left({x, x'}\right) \left({y, y'}\right) \left({x, x'}\right)^{-1}\) | \(=\) | \(\displaystyle \left({x, x'}\right) \left({y, y'}\right) \left({x^{-1}, x'^{-1} }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \left({x y x^{-1}, x' y' x'^{-1} }\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\in\) | \(\displaystyle H \times H'\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | by the normality of $H$ and $H'$. |
$(2): \quad \left({G \times G'}\right) / \left({H \times H'}\right)$ is isomorphic to $\left({G / H}\right) \times \left({G' / H'}\right)$:
Let $\varphi_1 : G \to G / H$ and $\varphi_2 : G' \to G' / H'$ be the quotient epimorphisms with $H$ and $H'$ as their kernels, respectively.
Now define a homomorphism $\varphi : G \times G' \to \left({G / H}\right) \times \left({G' / H'}\right)$ by $\varphi = \varphi_1 \times \varphi_2$.
The kernel of $\varphi$ is clearly $H \times H'$, and $\varphi$ is surjective.
So $\left({G / H}\right) \times \left({G' / H'}\right) \cong \left({G \times G'}\right) / \left({H \times H'}\right)$.
Sources
- Allan Clark: Elements of Abstract Algebra (1971)... (previous)... (next): $\S 47 \theta$