Subset of Set with Propositional Function
From ProofWiki
Theorem
Let $S$ be a set.
Let $P: S \to \left\{{\text{true}, \text{false}}\right\}$ be a propositional function on $S$.
Then:
- $\left\{{x \in S: P \left({x}\right)} \right\} \subseteq S$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\) | \(\displaystyle s \in \left\{ {x \in S: P \left({x}\right)} \right\}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle s \in \left\{ {x \in S \land P \left({x}\right)}\right\}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle s \in \left\{ {x \in S} \right\}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Rule of Simplification | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle s \in S\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of an element | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle \left\{ {x \in S: P \left({x}\right)}\right\} \subseteq S\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of a subset |
$\blacksquare$
Sources
- Allan Clark: Elements of Abstract Algebra (1971)... (previous)... (next): $\S 4$
- W.A. Sutherland: Introduction to Metric and Topological Spaces (1975): Notation and Terminology