Subset Relation is Transitive
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Theorem
The relation "is a subset of" is transitive:
- $\left({R \subseteq S}\right) \land \left({S \subseteq T}\right) \implies R \subseteq T$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\) | \(\displaystyle \left({R \subseteq S}\right) \land \left({S \subseteq T}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle \left({x \in R \implies x \in S}\right) \land \left({x \in S \implies x \in T}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of subset | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle \left({x \in R \implies x \in T}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Hypothetical Syllogism | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle R \subseteq T\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Definition of subset |
$\blacksquare$
Sources
- Paul R. Halmos: Naive Set Theory (1960)... (previous)... (next): $\S 1$: The Axiom of Extension
- George McCarty: Topology: An Introduction with Application to Topological Groups (1967): $\text{I}$: Exercises $\text{B iii}$
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 6.2$