Symmetric Difference is Associative/Proof 2

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Theorem

Symmetric difference is associative:

$R \symdif \paren {S \symdif T} = \paren {R \symdif S} \symdif T$


Proof

Expanding the right hand side:

\(\ds \) \(\) \(\ds \paren {R \symdif S} \symdif T\)
\(\ds \) \(=\) \(\ds \paren {\paren {\paren {R \cup S} \cap \paren {\overline R \cup \overline S} } \cup T} \cap \paren {\overline {R \symdif S} \cup \overline T}\) Definition 4 of Symmetric Difference
\(\ds \) \(=\) \(\ds \paren {\paren {\paren {R \cup S} \cap \paren {\overline R \cup \overline S} } \cup T} \cap \paren {\overline {\paren {\paren {R \cap \overline S} \cup \paren {\overline R \cap S} } } \cup \overline T}\) Definition 3 of Symmetric Difference
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {\overline R \cup \overline S \cup T} \cap \paren {\paren {\overline {\paren {R \cap \overline S} } \cap \overline {\paren {\overline R \cap S} } } \cup \overline T}\) Union Distributes over Intersection and De Morgan
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {\overline R \cup \overline S \cup T} \cap \paren {\paren {\paren {\overline R \cup S} \cap \paren {R \cup \overline S} } \cup \overline T}\) De Morgan
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {\overline R \cup \overline S \cup T} \cap \paren {\overline R \cup S \cup \overline T} \cap \paren {R \cup \overline S \cup \overline T}\) Union Distributes over Intersection


Expanding the left hand side:

\(\ds \) \(\) \(\ds R \symdif \paren {S \symdif T}\)
\(\ds \) \(=\) \(\ds \paren {R \cup \paren {\paren {S \cup T} \cap \paren {\overline S \cup \overline T} } } \cap \paren {\overline R \cup \overline {S \symdif T} }\) Definition 4 of Symmetric Difference
\(\ds \) \(=\) \(\ds \paren {R \cup \paren {\paren {S \cup T} \cap \paren {\overline S \cup \overline T} } } \cap \paren {\overline R \cup \overline {\paren {\paren {S \cap \overline T} \cup \paren {\overline S \cap T} } } }\) Definition 3 of Symmetric Difference
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {R \cup \overline S \cup \overline T} \cap \paren {\overline R \cup \paren {\overline {\paren {S \cap \overline T} } \cap \overline {\paren {\overline S \cap T} } } }\) Union Distributes over Intersection and De Morgan
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {R \cup \overline S \cup \overline T} \cap \paren {\overline R \cup \paren {\paren {\overline S \cup T} \cap \paren {S \cup \overline T} } }\) De Morgan
\(\ds \) \(=\) \(\ds \paren {R \cup S \cup T} \cap \paren {R \cup \overline S \cup \overline T} \cap \paren {\overline R \cup \overline S \cup T} \cap \paren {\overline R \cup S \cup \overline T}\) Union Distributes over Intersection


From Intersection is Commutative, it can be seen that the left hand side and right hand side are the same, and the result is proved.

$\blacksquare$