Talk:Brouwer's Fixed Point Theorem

The proof of the general case should not use a line passing through x and f(x). The correct proof uses the ray starting at f(x) and passing through x. Then one can properly define h(x) as the point farthest out on this ray which intersects the boundary. Without this change, h(x) is ill-defined; the line intersects the boundary at two points. -- 07:31, 19 August 2011 Amonic

Way over my head I'm afraid, and the person who originally put that proof together has limited his contributions to this site in recent times. Please feel free to amend it as you see fit.

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