Talk:Evaluation Linear Transformation
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what is $t'$? --Cynic 04:25, 12 November 2008 (UTC)
"For each $x \in G$, we define the mapping $x^\wedge: G^* \to R$ as
$\forall t' \in G^*: x^\wedge \left({t'}\right) = t' \left({x}\right)$."
So it's some arbitrary element of $G^*$, which is the set of all mappings from the $R$-module $G$ to its scalar ring $R$.
