Unbounded Monotone Sequence Diverges to Infinity
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Theorem
Let $\left \langle {x_n} \right \rangle$ be a sequence in $\R$.
Let $\left \langle {x_n} \right \rangle$ be monotone, i.e. either increasing or decreasing.
Increasing
Let $\left \langle {x_n} \right \rangle$ be increasing and unbounded above.
Then $x_n \to \infty$ as $n \to \infty$.
Decreasing
Let $\left \langle {x_n} \right \rangle$ be decreasing and unbounded below.
Then $x_n \to -\infty$ as $n \to \infty$.
Proof
- Let $\left \langle {x_n} \right \rangle$ be increasing and unbounded above.
Let $H > 0$.
As $\left \langle {x_n} \right \rangle$ is unbounded above, $\exists N: x_N > H$.
As $\left \langle {x_n} \right \rangle$ is increasing, then $\forall n \ge N: x_n \ge x_N > H$.
It follows from the definition of divergent to infinity that $x_n \to \infty$ as $n \to \infty$.
- The same argument can be used for the case where $\left \langle {x_n} \right \rangle$ is decreasing and unbounded below.
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 4.29 \ (5)$