Upper and Lower Bounds of Integral

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Theorem

Let $f$ be a real function which is continuous on the closed interval $\left[{a .. b}\right]$.

Let $f$ have a maximum of $M$ and a minimum of $m$ on $\left[{a .. b}\right]$.

Let $\displaystyle \int_a^b f \left({x}\right) \ \mathrm dx$ be the definite integral of $f \left({x}\right)$ over $\left[{a .. b}\right]$.


Then:

$\displaystyle m \left({b - a}\right) \le \int_a^b f \left({x}\right)\ \mathrm dx \le M \left({b - a}\right)$


Corollary

Let $f$ be a real function which is continuous on the closed interval $\left[{a .. b}\right]$.

Suppose that $\forall t \in \left[{a .. b}\right]: \left|{f \left({t}\right)}\right| < \kappa$.


Then:

$\displaystyle \forall \xi, x \in \left[{a .. b}\right]: \left|{\int_x^\xi f \left({t}\right)\ \mathrm dt}\right| < \kappa \left|{x - \xi}\right|$


Proof

This follows directly from the definition of definite integral.

  • By definition, the upper sum is $M \left({b - a}\right)$, and the lower sum is $m \left({b - a}\right)$.

The result follows.

$\blacksquare$


Proof of Corollary

Follows directly from the main proof.

$\blacksquare$


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