Upper and Lower Bounds of Integral
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Theorem
Let $f$ be a real function which is continuous on the closed interval $\left[{a .. b}\right]$.
Let $f$ have a maximum of $M$ and a minimum of $m$ on $\left[{a .. b}\right]$.
Let $\displaystyle \int_a^b f \left({x}\right) \ \mathrm dx$ be the definite integral of $f \left({x}\right)$ over $\left[{a .. b}\right]$.
Then:
- $\displaystyle m \left({b - a}\right) \le \int_a^b f \left({x}\right)\ \mathrm dx \le M \left({b - a}\right)$
Corollary
Let $f$ be a real function which is continuous on the closed interval $\left[{a .. b}\right]$.
Suppose that $\forall t \in \left[{a .. b}\right]: \left|{f \left({t}\right)}\right| < \kappa$.
Then:
- $\displaystyle \forall \xi, x \in \left[{a .. b}\right]: \left|{\int_x^\xi f \left({t}\right)\ \mathrm dt}\right| < \kappa \left|{x - \xi}\right|$
Proof
This follows directly from the definition of definite integral.
- From the Continuity Property it follows that $m$ and $M$ both exist.
- The closed interval $\left[{a .. b}\right]$ is a subdivision of itself.
- By definition, the upper sum is $M \left({b - a}\right)$, and the lower sum is $m \left({b - a}\right)$.
The result follows.
$\blacksquare$
Proof of Corollary
Follows directly from the main proof.
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 13.4, \ \S 13.6$