User:Lord Farin/Tableau Proof Rules/Conjunction
From ProofWiki
Conjunction
Given statements $p$ and $q$, we have also $p \land q$ and $q \land p$.
| Line | Pool | Formula | Rule | Depends upon | Notes | |
|---|---|---|---|---|---|---|
| $i$ | $I$ | $p$ | ? | ? | ||
| $j$ | $J$ | $q$ | ? | ? | ||
| $k$ | $I,J$ | $p \land q$ | $\land \mathcal I$ | $i,j$ | ||
| $l$ | $I,J$ | $q \land p$ | $\land \mathcal I$ | $i,j$ |
Wiki code
|- | align="right" | $k$ || | align="right" | $I,J$ | $p \land q$ | [[Axiom:Rule of Conjunction|$\land \mathcal I$]] | $i,j$ |- | align="right" | $l$ || | align="right" | $I,J$ | $q \land p$ | [[Axiom:Rule of Conjunction|$\land \mathcal I$]] | $i,j$