110

From ProofWiki
Jump to navigation Jump to search

Previous  ... Next

Number

$110$ (one hundred and ten) is:

$2 \times 5 \times 11$


The $4$th positive integer after $1$, $7$, $102$ the divisor sum is a cube:
$\map {\sigma_1} {110} = 216 = 6^3$
It is also the $3$rd such, after $1$, $102$, whose divisor count is also a cube:
$\map {\sigma_0} {110} = 8 = 2^3$


The $8$th sphenic number after $30$, $42$, $66$, $70$, $78$, $102$, $105$:
$110 = 2 \times 5 \times 11$


The $21$st positive integer $n$ such that no factorial of an integer can end with $n$ zeroes.


Arithmetic Functions on $110$

\(\ds \map {\sigma_0} { 110 }\) \(=\) \(\ds 8\) $\sigma_0$ of $110$
\(\ds \map {\sigma_1} { 110 }\) \(=\) \(\ds 216\) $\sigma_1$ of $110$


Also see


Sources