256

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Number

$256$ (two hundred and fifty-six) is:

$2^8$


In binary:
$10 \, 000 \, 000$


In hexadecimal:
$100$


The $2$nd eighth power after $1$:
$256 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$


The $2$nd power of $16$ after $(1)$, $16$:
$256 = 16^2$


The $3$rd positive integer after $128$, $192$ with $7$ or more prime factors:
$256 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \paren {\times \, 2}$


The $3$rd (and possibly last) power of $2$ after $1$, $4$ which is the sum of distinct powers of $3$:
$256 = 2^8 = 3^0 + 3^1 + 3^2 + 3^5$


The $4$th fourth power after $1$, $16$, $81$:
$256 = 4 \times 4 \times 4 \times 4$


The $4$th power of $4$ after $(1)$, $4$, $16$, $64$:
$256 = 4^4$


The $6$th square number after $1$, $4$, $36$, $121$, $144$ to be the divisor sum value of some (strictly) positive integer:
$256 = \map {\sigma_1} {217}$


The $8$th power of $2$ after $(1)$, $2$, $4$, $8$, $16$, $32$, $64$, $128$:
$256 = 2^8$


The $9$th almost perfect number after $1$, $2$, $4$, $8$, $16$, $32$, $64$, $128$:
$\map {\sigma_1} {256} = 511 = 2 \times 256 - 1$


The $10$th positive integer after $64$, $96$, $128$, $144$, $160$, $192$, $216$, $224$, $240$ with $6$ or more prime factors:
$256 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \paren {\times \, 2 \times 2}$


The $16$th square number after $1$, $4$, $9$, $16$, $25$, $36$, $49$, $64$, $81$, $100$, $121$, $144$, $169$, $196$, $225$:
$256 = 16 \times 16$


The $27$th powerful number after $1$, $4$, $8$, $9$, $16$, $25$, $\ldots$, $144$, $169$, $196$, $200$, $216$, $225$, $243$


Also see


Sources