Algebra Defined by Ring Homomorphism on Commutative Ring is Commutative

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $R$ be a commutative ring.

Let $\struct {S, +, *}$ be a commutative ring.

Let $f: R \to S$ be a ring homomorphism.

Let $\struct {S_R, *}$ be the algebra defined by the ring homomorphism $f$.


Then $\struct {S_R, *}$ is a commutative algebra.


Proof

Note that by Center of Commutative Ring, the image of $f$ is indeed a subset of the center of $S$.

By definition, the multiplication of $\struct {S_R, *}$ is the ring product of $S$.

Thus it follows immediately from the fact that $S$ is a ring, that $\struct {S_R, *}$ is a commutative algebra.

$\blacksquare$


Also see