All Infima Preserving Mapping is Upper Adjoint of Galois Connection/Lemma 2
Jump to navigation
Jump to search
Theorem
Let $\struct {S, \preceq}$ be a complete lattice.
Let $\struct {T, \precsim}$ be an ordered set.
Let $g: S \to T$ be an all infima preserving mapping.
Let us define a mapping $d: T \to S$ as:
- $\forall t \in T: \map d t := \map \inf {g^{-1} \sqbrk {t^\succsim} }$
Then:
- $\forall t \in T: \map d t = \map \min {g^{-1} \sqbrk {t^\succsim} }$
Proof
- $\forall t \in T: \map d t = \map \min {g^{-1} \sqbrk {t^\succsim} }$
Let $t \in T$.
By definition of $d$:
- $\map d t = \map \inf {g^{-1} \sqbrk {t^\succsim} }$
- $g \sqbrk {g^{-1} \sqbrk {t^\succsim} } \subseteq t^\succsim$
By Infimum of Subset and Infimum of Upper Closure of Element:
- $t = \map \inf {t^\succsim} \precsim \map \inf {g \sqbrk {g^{-1} \sqbrk {t^\succsim} } }$
By definition of upper closure of element:
- $\map \inf {g \sqbrk {g^{-1} \sqbrk {t^\succsim} } } \in t^\succsim$
By definition of complete lattice:
- $g^{-1} \sqbrk {t^\succsim}$ admits an infimum
By definitions mapping preserves the infimum:
- $\map \inf {g \sqbrk {g^{-1} \sqbrk {t^\succsim} } } = \map g {\map d t}$
Thus by definition of image of set:
- $\map d t \in g^{-1} \sqbrk {t^\succsim}$
Thus
- $\map d t = \map \min {g^{-1} \sqbrk {t^\succsim} }$
$\blacksquare$
Sources
- 1980: G. Gierz, K.H. Hofmann, K. Keimel, J.D. Lawson, M.W. Mislove and D.S. Scott: A Compendium of Continuous Lattices
- Mizar article WAYBEL_1:14