Area of Annulus

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Theorem

Let $A$ be an annulus whose inner radius is $r$ and whose outer radius is $R$.


The area of $A$ is given by:

$\map \Area A = \pi \paren {R^2 - r^2}$


Proof

Annulus.png

The area of $A$ is seen to be:

the area of the outer circle with the area of the inner circle removed.

From Area of Circle:

the area of the outer circle is $\pi R^2$
the area of the inner circle is $\pi r^2$

The result follows.

$\blacksquare$


Sources