Area under Curve

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Let $f: \R \to \R$ be a real function which is defined and (Darboux) integrable on the closed interval $\closedint a b$.

Consider the graph of $f$ embedded in a Cartesian plane.

Let $\AA$ denote the area between the curve $\map f x$, the straight lines $x = a$ and $x = b$, and the $x$-axis.


$\AA = \ds \int_a^b \map f x \rd x$

where $\ds \int_a^b \map f x \rd x$ denotes the (Darboux) definite integral of $f$ from $a$ to $b$.



Let $x \in \closedint a b$.

Let $\delta x$ be an arbitrarily small positive real number such that $x + \delta x \in \closedint a b$.

Consider the small strip between:

the $x$-axis
the vertical straight lines through $\tuple {x, 0}$ and $\tuple {x + \delta x, 0}$
the curve $\map f x$.

The area of this strip is approximated by $y \delta x$.

Hence we create a model of the geometric interpretation of the definite integral.


Area under $y = \paren {x - 1} \paren {x - 2}$

The area between the $x$-axis and the curve $y = \paren {x - 1} \paren {x - 2}$ is $\dfrac 1 6$.

Area under $y = \sin x$ between $0$ and $\pi$

The area bounded by the curve $y = \sin x$ and the $x$-axis between $x = 0$ and $x = \pi$ is $2$.

Area between $x = y^2$ and $x^2 = 8 y$

Area under Curve/Examples/Between x=y^2 and x^2=8y