Biconditional Elimination/Sequent Form/Proof 1/Form 2

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Theorem

$p \iff q \vdash q \implies p$


Proof

By the tableau method of natural deduction:

$p \iff q \vdash q \implies p$
Line Pool Formula Rule Depends upon Notes
1 1 $p \iff q$ Premise (None)
2 1 $q \implies p$ Biconditional Elimination: $\iff \EE_2$ 1

$\blacksquare$