Binomial Theorem/Hurwitz's Generalisation/Mistake
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Source Work
1997: Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms (3rd ed.):
- Chapter Two: Information Structures
- $2.3.$ Trees:
- $2.3.4.$ Basic Mathematical Properties of Trees
- $2.3.4.4.$ Enumeration of Trees
- Exercise $30$: Solution
- $2.3.4.4.$ Enumeration of Trees
- $2.3.4.$ Basic Mathematical Properties of Trees
- $2.3.$ Trees:
Mistake
- Use this to prove Hurwitz' generalization of the binomial theorem:
- $\ds \sum x \paren {x + \epsilon_1 z_1 + \cdots + \epsilon_n z_n}^{\epsilon_1 + \cdots + \epsilon_n - 1} y \paren {y + \paren {1 - \epsilon_1} z_1 - \cdots + \paren {1 - \epsilon_n} z_n}^{n - \epsilon_1 - \cdots - \epsilon_n} = \paren {x + y} \paren {x + y + z_1 + \cdots + z_n}^{n - 1}$
Correction
There is an extraneous $y$ here. It should read:
- $\ds \sum x \paren {x + \epsilon_1 z_1 + \cdots + \epsilon_n z_n}^{\epsilon_1 + \cdots + \epsilon_n - 1} \paren {y + \paren {1 - \epsilon_1} z_1 - \cdots + \paren {1 - \epsilon_n} z_n}^{n - \epsilon_1 - \cdots - \epsilon_n} = \paren {x + y} \paren {x + y + z_1 + \cdots + z_n}^{n - 1}$