Brocard's Problem
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Unsolved Problem
For which pairs of (strictly) positive integers $\tuple {m, n}$ do the following hold:
- $n! + 1 = m^2$
The only known pairs are:
\(\text {(1)}: \quad\) | \(\, \ds \tuple {5, 4}: \, \) | \(\ds 4! + 1\) | \(=\) | \(\ds 24 + 1 = 25 = 5^2\) | ||||||||||
\(\text {(2)}: \quad\) | \(\, \ds \tuple {11, 5}: \, \) | \(\ds 5! + 1\) | \(=\) | \(\ds 120 + 1 = 121 = 11^2\) | ||||||||||
\(\text {(3)}: \quad\) | \(\, \ds \tuple {71, 7}: \, \) | \(\ds 7! + 1\) | \(=\) | \(\ds 5040 + 1 = 5041 = 71^2\) |
Also see
Source of Name
This entry was named for Pierre René Jean Baptiste Henri Brocard.
Sources
- 1980: David M. Burton: Elementary Number Theory (revised ed.) ... (previous) ... (next): Chapter $1$: Some Preliminary Considerations: $1.1$ Mathematical Induction: Problems $1.1$: $5 \ \text {(a)}$
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $4$
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $7$
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $121$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $4$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $7$
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $121$
- Weisstein, Eric W. "Brocard's Problem." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/BrocardsProblem.html