Cardinal Product Equal to Maximum

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Theorem

Let $S$ and $T$ be sets that are equinumerous to their cardinal number.

Let $\card S$ denote the cardinal number of $S$.

Suppose $S$ is infinite.

Suppose $T > 0$.


Then:

$\card {S \times T} = \map \max {\card S, \card T}$


Proof

Let $x$ denote $\map \max {\card S, \card T}$.

Then by Cartesian Product Preserves Cardinality:

$S \times T \sim \card S \times \card T$

Let $f: S \times T \to \card S \times \card T$ be a bijection.

It follows that $f: S \times T \to x \times x$ is an injection.


Hence:

\(\ds \card {S \times T}\) \(\le\) \(\ds \card {x \times x}\) Injection iff Cardinal Inequality
\(\ds \) \(=\) \(\ds \card x\) Non-Finite Cardinal is equal to Cardinal Product
\(\ds \) \(\le\) \(\ds x\) Cardinal Number Less than Ordinal: Corollary

Therefore:

$\card {S \times T} \le x$

$\Box$


Conversely:

$x = \card S$ if $\card T \le \card S$

and:

$x = \card T$ if $\card S \le \card T$

By Relation between Two Ordinals:

$x = \card S$ or $x = \card T$

It follows by Set Less than Cardinal Product that:

$x \le \card {S \times T}$

$\Box$


Combining the two lemmas, it follows that:

$x = \card {S \times T}$

$\blacksquare$


Sources