Cardinality Less One
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Theorem
Let $S$ be a finite set.
Let:
- $\card S = n + 1$
where $\card S$ is the cardinality of $S$.
Let $a \in S$.
Then:
- $\card {S \setminus \set a} = n$
where $\setminus$ denotes set difference.
Proof
This follows as an immediate consequence of Set Equivalence Less One Element.
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {III}$: The Natural Numbers: $\S 17$: Finite Sets: Theorem $17.4$