Ceiling minus Real Number
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Theorem
- $\forall x \in \R: \ceiling x - x \in \hointr 0 1$
where $\ceiling x$ denotes the ceiling of $x$.
Proof
\(\ds \ceiling x - 1\) | \(<\) | \(\ds x \le \ceiling x\) | Real Number is between Ceiling Functions | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \ceiling x - 1 - \ceiling x\) | \(<\) | \(\ds x - \ceiling x \le \ceiling x - \ceiling x\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds -1\) | \(<\) | \(\ds x - \ceiling x \le 0\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds 1\) | \(>\) | \(\ds \ceiling x - x \ge 0\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \ceiling x - x\) | \(\in\) | \(\ds \hointr 0 1\) |
$\blacksquare$