Change of Basis Matrix under Linear Transformation/Corollary
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Corollary to Change of Basis Matrix under Linear Transformation
Let $R$ be a commutative ring with unity.
Let $G$ be a free unitary $R$-module of finite dimension $n$.
Let $\sequence {a_n}$ and $\sequence { {a_n}'}$ be ordered bases of $G$.
Let $u: G \to G$ be a linear operator on $G$.
Let $\sqbrk {u; \sequence {a_n} }$ denote the matrix of $u$ relative to $\sequence {a_n}$.
Let:
- $\mathbf A = \sqbrk {u; \sequence {a_n} }$
- $\mathbf B = \sqbrk {u; \sequence { {a_n}'} }$
Then:
- $\mathbf B = \mathbf P^{-1} \mathbf A \mathbf P$
where $\mathbf P$ is the matrix corresponding to the change of basis from $\sequence {a_n}$ to $\sequence { {a_n}'}$.
Proof
This is an instance of Change of Basis Matrix under Linear Transformation.
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {V}$: Vector Spaces: $\S 29$. Matrices: Theorem $29.4$: Corollary