Class Difference with Class Difference with Subclass

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Theorem

Let $A$ and $B$ be classes.

Let $B \subseteq A$.

Then:

$A \setminus \paren {A \setminus B} = B$


Proof

From Class Difference with Class Difference:

$A \setminus \paren {A \setminus B} = A \cap B$

for all classes $A$ and $B$.

From Intersection with Subclass is Subclass:

$A \subseteq B \iff A \cap B = A$

The result follows.

$\blacksquare$


Also see


Sources