Complex Arithmetic/Examples/Imaginary (z 1 z 2 over z 3)
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Example of Complex Arithmetic
Let $z_1 = 1 - i$, $z_2 = -2 + 4 i$ and $z_3 = \sqrt 3 - 2 i$.
Then:
- $\map \Im {\dfrac {z_1 z_2} {z_3} } = \dfrac {6 \sqrt 3 + 4} 7$
Proof
\(\ds \map \Im {\dfrac {z_1 z_2} {z_3} }\) | \(=\) | \(\ds \map \Im {\dfrac {\paren {1 - i} \paren {-2 + 4 i} } {\sqrt 3 - 2 i} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Im {\dfrac {\paren {-2 + 2 i + 4 i - 4 i^2} } {\sqrt 3 - 2 i} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Im {\dfrac {2 + 6 i} {\sqrt 3 - 2 i} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Im {\dfrac {\paren {2 + 6 i} \paren {\sqrt 3 + 2 i} } {\paren {\sqrt 3 - 2 i} \paren {\sqrt 3 + 2 i} } }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Im {\dfrac {2 \sqrt 3 + 4 i + 6 \sqrt 3 i + 12 i^2} {3 + 2^2} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Im {\dfrac {2 \sqrt 3 - 12 + \paren {6 \sqrt 3 + 4} i} 7}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {6 \sqrt 3 + 4} 7\) |
$\blacksquare$
Sources
- 1981: Murray R. Spiegel: Theory and Problems of Complex Variables (SI ed.) ... (previous) ... (next): $1$: Complex Numbers: Supplementary Problems: Fundamental Operations with Complex Numbers: $54 \ \text {(j)}$